// Copyright 2017-2021 DERO Project. All rights reserved. // Use of this source code in any form is governed by RESEARCH license. // license can be found in the LICENSE file. // GPG: 0F39 E425 8C65 3947 702A 8234 08B2 0360 A03A 9DE8 // // // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND ANY // EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF // MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL // THE COPYRIGHT HOLDER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, // SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, // PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS // INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, // STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF // THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. package crypto import "github.com/deroproject/derohe/crypto/bn256" // BUG BUG BUG this needs to be updated and add more context // this function is used to encrypt/decrypt payment id // as the operation is symmetric XOR, is the same in both direction // func EncryptDecryptPaymentID(blinder *bn256.G1, input []byte) (output []byte) { // input must be exactly 8 bytes long if len(input) != 8 { panic("Encrypted payment ID must be exactly 8 bytes long") } output = make([]byte, 8, 8) blinder_compressed := blinder.EncodeCompressed() if len(blinder_compressed) != 33 { panic("point compression needs to be fixed") } // Todo we should take the hash blinder_compressed = blinder_compressed[25:] // we will use last 8 bytes for l := range input { output[l] = input[l] ^ blinder_compressed[l] // xor the bytes with the hash } /* var tmp_buf [33]byte copy(tmp_buf[:], derivation[:]) // copy derivation key to buffer tmp_buf[32] = ENCRYPTED_PAYMENT_ID_TAIL // take hash hash := crypto.Keccak256(tmp_buf[:]) // take hash of entire 33 bytes, 32 bytes derivation key, 1 byte tail output = make([]byte, 8, 8) for i := range input { output[i] = input[i] ^ hash[i] // xor the bytes with the hash } */ return }